document.write( "Question 767975: Demand Equation The price (in dollars) and the quantity x sold of a certain product obey the demand equation p= -1/10x+150, 0≤x≤1500\r
\n" ); document.write( "\n" ); document.write( "Revenue is x*p.
\n" ); document.write( "(a) Express the revenue R as a function of x.
\n" ); document.write( "(b) What quantity x maximizes revenue? What is the maximum revenue?\r
\n" ); document.write( "\n" ); document.write( "***PLEASE SHOW STEPS!!
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Algebra.Com's Answer #467983 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"++p=+%28-1%2F10%29%2Ax%2B150+\", 0≤x≤1500
\n" ); document.write( "\"+R+=+p%2Ax+\"
\n" ); document.write( "\"+R+=+%28+%28-1%2F10%29%2Ax+%2B+150+%29%2Ax+\"
\n" ); document.write( "\"+R+=+%28+-1%2F10+%29%2Ax%5E2+%2B+150x+\"
\n" ); document.write( "This is a parabola with a maximum since
\n" ); document.write( "the coefficient of the \"+x%5E2+\" term is minus.
\n" ); document.write( "Compare the equation with the general form:
\n" ); document.write( "\"+y+=+ax%5E2+%2B+b%2Ax+%2B+c+\"
\n" ); document.write( "\"+a+=+-1%2F10+\"
\n" ); document.write( "\"+b+=+150+\"
\n" ); document.write( "\"+c+=+0+\"
\n" ); document.write( "-----------
\n" ); document.write( "The x-coordinate of the maximum is at
\n" ); document.write( "\"+-b%2F%282a%29+=+-150+%2F+%28+2%2A%28-1%2F10%29%29+\"
\n" ); document.write( "\"+-b%2F%282a%29+=+150+%2F+%281%2F5%29+\"
\n" ); document.write( "\"+-b%2F%282a%29+=+750+\"
\n" ); document.write( "This is the value of \"x\" that maximizes revenue
\n" ); document.write( "Plug this back into the equation
\n" ); document.write( "\"+R%5Bmax%5D+=+%28+-1%2F10+%29%2Ax%5E2+%2B+150x+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+%28+-1%2F10+%29%2A750%5E2+%2B+150%2A750+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+-562500%2F10+%2B+112500+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+-56250+%2B+112500+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+56250+\"
\n" ); document.write( "The maximum revenue is $56,250\r
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