document.write( "Question 65999: Martina leaves home at 9 A.M., bicycling at a rate of
\n" ); document.write( "24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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Algebra.Com's Answer #46795 by stanbon(75887)\"\" \"About 
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Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h.
\n" ); document.write( "Two hours later, John leaves, driving at the rate of 48 mi/h.
\n" ); document.write( "At what time will John catch up with Martina?
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\n" ); document.write( "Martina DATA:
\n" ); document.write( "In the 1st two hours Martina travels 48 miles.
\n" ); document.write( "After that she travels x miles.
\n" ); document.write( "Her total distance is x+48 miles
\n" ); document.write( "Her Rate is 24 mph.
\n" ); document.write( "Her time is (x+48)/24 hrs.
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\n" ); document.write( "John's DATA:
\n" ); document.write( "His distance must be the same as Martina's: x+48 miles
\n" ); document.write( "His Rate is 48 mph.
\n" ); document.write( "His time is (x+48)/48 hrs.
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\n" ); document.write( "EQUATIONn:
\n" ); document.write( "John's time = Martina's time-2
\n" ); document.write( "(x+48)/48 = (x+48)/24 -2
\n" ); document.write( " (x+48)=2(x+48)-96
\n" ); document.write( "x+48=96
\n" ); document.write( "x=48 miles
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\n" ); document.write( "Answer to question:
\n" ); document.write( "Martina time = (x+48)/24 = (96)/24=4 hrs
\n" ); document.write( "9:00+4 hrs = 1:00 PM
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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