document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767295>Question 767295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the equation of the directrix of a parabola y^2=6x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467948 by </B><A HREF=/tutors/aboutme.mpl?userid=DSMLMD><B>DSMLMD(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DSMLMD><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=DSMLMD><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the equation of the directrix of parabola, first we must find p value from the parabola equation. Next, we substitute the p value to directrix formula x = -p and change the p value position to left side become x + p = 0. <BR>\n" );
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document.write( "Parabola equation:<BR>\n" );
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document.write( "y^2 = 6x<BR>\n" );
document.write( "y^2 = 4(3/2)x<BR>\n" );
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document.write( "Directrix line:<BR>\n" );
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document.write( "x = -p<BR>\n" );
document.write( "x = -(3/2)<BR>\n" );
document.write( "x + (3/2) = 0<BR>\n" );
document.write( "2x + 3 = 0 (multiplied 2 to both side)<BR>\n" );
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document.write( "So the equation of the directrix or a parabola y^2 = 6x is 2x + 3 = 0 </SPAN>\n" );
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