document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767877>Question 767877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A carpenter is constructing a frame for a rectangular picture. If the sides of the picture have a ratio of 4:3 and the shorter side is 42 cm long, how much framing material does he need to complete the frame? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467915 by </B><A HREF=/tutors/aboutme.mpl?userid=anukamal><B>anukamal(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anukamal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l be the length of rectangular frame<BR>\n" );
document.write( "let b  be the breadth of rectangular frame.<BR>\n" );
document.write( "= l:b=4:3<BR>\n" );
document.write( "=   l=4/3b<BR>\n" );
document.write( "As  b=42cm<BR>\n" );
document.write( "so, l=4/3*42<BR>\n" );
document.write( "    l=56cm<BR>\n" );
document.write( "Total frame required will be<BR>\n" );
document.write( "     =2(l+b)<BR>\n" );
document.write( "     =2(56+42)<BR>\n" );
document.write( "     =2(98)<BR>\n" );
document.write( "     =196cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );