document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767675>Question 767675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of two complementary angles if one is 10 degrees more than three times the other </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467759 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Other angle = x<BR>\n" );
document.write( "Larger angle = 10 + 3x<BR>\n" );
document.write( "Complementary angles = 90 degrees<BR>\n" );
document.write( "So, x + (10 + 3x) = 90<BR>\n" );
document.write( "x + 10 + 3x = 90<BR>\n" );
document.write( "4x = 90 - 10<BR>\n" );
document.write( "4x = 80<BR>\n" );
document.write( " x = 20<BR>\n" );
document.write( "Other angle = 20 degrees<BR>\n" );
document.write( "Larger angle = 70 degrees.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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