document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66032>Question 66032</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> simplify\r<BR>\n" );
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document.write( "5 times the square root of 7/20 - 2 times the square root of 20/7 - 3 times the square root of 560 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46775 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simplify\r<BR>\n" );
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document.write( "5 times the square root of 7/20 - 2 times the square root of 20/7 - 3 times the square root of 560\r<BR>\n" );
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document.write( "5sqrt(7/20)-2sqrt(20/7)-3sqrt560=<BR>\n" );
document.write( "5sqrt(7/20)-2sqrt(20/7)-3sqrt((20)(4)(7))  which equals:<BR>\n" );
document.write( "5sqrt(7/20)-2sqrt(20/7)-6sqrt((20)(7)) \r<BR>\n" );
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document.write( "We need a common denominator.  We can get this by multiplying the numerator and denominator of each term by sqrt((20)(7)) --- the LCM.  This gives us:\r<BR>\n" );
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document.write( "5(sqrt7)(sqrt7)-2(sqrt20)(sqrt20)-6(sqrt((20)(7))(sqrt((20)(7))) which equals:\r<BR>\n" );
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document.write( "[5(7)-2(20)-6(20)(7)]/sqrt((20)(7) simplifying we get:<BR>\n" );
document.write( "(35-40-840)/sqrt(140)=-845/sqrt(140)\r<BR>\n" );
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document.write( "Multiply numerator and denominator by sqrt(140) to get rid of the radical in the denominator and we get:\r<BR>\n" );
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document.write( "-845sqrt(140)/140  =<BR>\n" );
document.write( "-845sqrt((4)(35))/140= <BR>\n" );
document.write( "-1690sqrt(35)/140= divide both numerator and denominator by 10\r<BR>\n" );
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document.write( "-169sqrt(35)/14\r<BR>\n" );
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document.write( "That should be it unless I made a mistake.\r<BR>\n" );
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document.write( "CK by using a calculator\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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