document.write( "Question 767651: A rectangular piece of tin is 3 cm longer than its width. From each corner, 3 cm^2 is cut out. The sides are turned up to form a box whose volume is 120 cm^3. Find the dimensions of the box. \n" ); document.write( "
Algebra.Com's Answer #467747 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = 3 + x
\n" ); document.write( "Removal of 3cm^2 from each corner.
\n" ); document.write( "Width = x - 6
\n" ); document.write( "Length = 3 + x - 6 = x - 3
\n" ); document.write( "Volume = length*width*height
\n" ); document.write( "120 = (x - 3)*(x - 6)*(3)
\n" ); document.write( "120 = 3x^2 - 27x + 54
\n" ); document.write( "Combine
\n" ); document.write( "3x^2 - 27x + 54 - 120 = 0
\n" ); document.write( "3x^2 - 27x - 66 = 0
\n" ); document.write( "3(x^2 - 9x - 22) = 0
\n" ); document.write( "3(x - 11)(x + 2) = 0
\n" ); document.write( "x + 2 = 0
\n" ); document.write( "x = -2 (no answer x<0)
\n" ); document.write( "x - 11 = 0
\n" ); document.write( "x = 11
\n" ); document.write( "Width = 5cm
\n" ); document.write( "Length = 8cm
\n" ); document.write( "Height = 3cm
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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