document.write( "Question 767651: A rectangular piece of tin is 3 cm longer than its width. From each corner, 3 cm^2 is cut out. The sides are turned up to form a box whose volume is 120 cm^3. Find the dimensions of the box. \n" ); document.write( "
Algebra.Com's Answer #467747 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Width = x \n" ); document.write( "Length = 3 + x \n" ); document.write( "Removal of 3cm^2 from each corner. \n" ); document.write( "Width = x - 6 \n" ); document.write( "Length = 3 + x - 6 = x - 3 \n" ); document.write( "Volume = length*width*height \n" ); document.write( "120 = (x - 3)*(x - 6)*(3) \n" ); document.write( "120 = 3x^2 - 27x + 54 \n" ); document.write( "Combine \n" ); document.write( "3x^2 - 27x + 54 - 120 = 0 \n" ); document.write( "3x^2 - 27x - 66 = 0 \n" ); document.write( "3(x^2 - 9x - 22) = 0 \n" ); document.write( "3(x - 11)(x + 2) = 0 \n" ); document.write( "x + 2 = 0 \n" ); document.write( "x = -2 (no answer x<0) \n" ); document.write( "x - 11 = 0 \n" ); document.write( "x = 11 \n" ); document.write( "Width = 5cm \n" ); document.write( "Length = 8cm \n" ); document.write( "Height = 3cm \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " \n" ); document.write( " |