document.write( "Question 767604: A father is twice as old as his son 12 years ago the father was 4 times as old as the son was then - determine the present age \n" ); document.write( "
Algebra.Com's Answer #467720 by anukamal(7)![]() ![]() ![]() You can put this solution on YOUR website! Let the son's present age be x years \n" ); document.write( "then father's age is 2x years. \n" ); document.write( "12 years ago, \n" ); document.write( "The son's age is 2(x-12)=4(x-12) \n" ); document.write( "2x-24=4x-48 \n" ); document.write( "2x-4x=-48+24 \n" ); document.write( "-2x=-24 \n" ); document.write( "therefore x=12 \n" ); document.write( "Son's age is 12 years \n" ); document.write( "Father's age is 24 years \n" ); document.write( " |