document.write( "Question 767604: A father is twice as old as his son 12 years ago the father was 4 times as old as the son was then - determine the present age \n" ); document.write( "
Algebra.Com's Answer #467720 by anukamal(7)\"\" \"About 
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Let the son's present age be x years
\n" ); document.write( "then father's age is 2x years.
\n" ); document.write( "12 years ago,
\n" ); document.write( "The son's age is 2(x-12)=4(x-12)
\n" ); document.write( "2x-24=4x-48
\n" ); document.write( "2x-4x=-48+24
\n" ); document.write( "-2x=-24
\n" ); document.write( "therefore x=12
\n" ); document.write( "Son's age is 12 years
\n" ); document.write( "Father's age is 24 years
\n" ); document.write( "
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