document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767413>Question 767413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor the trigonometric expression\r<BR>\n" );
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document.write( "64 sec^2y - 16 sec y + 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467714 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor the trigonometric expression <BR>\n" );
document.write( "64 sec^2y - 16 sec y + 1<BR>\n" );
document.write( "Use quadratic formula to solve for sec(y)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a=64, b=-16, c=1<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "(sec(y)-1/8)(sec(y)-1/8) </SPAN>\n" );
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