document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767539>Question 767539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John drove to a distant city in 9 hours. When he returned, there was less traffic, and the trip took only 7 hours. If he drove 12 mph faster on the return trip, how fast did he drive each way? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467707 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> John drove to a distant city in 9 hours. When he returned, there was less traffic, and the trip took only 7 hours. If he drove 12 mph faster on the return trip, how fast did he drive each way?<BR>\n" );
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document.write( "let x=speed of going trip<BR>\n" );
document.write( "x+12= speed of return trip<BR>\n" );
document.write( "distance=travel time*speed(same for both directions)<BR>\n" );
document.write( "9x=7(x+12)<BR>\n" );
document.write( "9x=7x+84<BR>\n" );
document.write( "2x=84<BR>\n" );
document.write( "x=42<BR>\n" );
document.write( "x+12=54<BR>\n" );
document.write( "speed of going trip=42 mph<BR>\n" );
document.write( "speed of return trip=54 mph </SPAN>\n" );
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