document.write( "Question 66011This question is from textbook Beginning Algebra
\n" ); document.write( ": Write the equation of the line with given slope and y-intercept. Then graph each line using the slope and y-intercept.\r
\n" ); document.write( "\n" ); document.write( "I am not quite sure what they mean by write out the equation of the line.\r
\n" ); document.write( "\n" ); document.write( "Slope: -2; y-intercept: (0, 4). I can do the graph but I do not quite understand what they mean by writing out the equation. Any help is appreciated. Thanks.
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Algebra.Com's Answer #46770 by funmath(2933)\"\" \"About 
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Write the equation of the line with given slope and y-intercept. Then graph each line using the slope and y-intercept.\r
\n" ); document.write( "\n" ); document.write( "Slope: -2; y-intercept: (0, 4)
\n" ); document.write( "The slope-intercept form of a line is: \"highlight%28y=mx%2Bb%29\", where m=slope and (0,b)=y-intercpet, your slope, m=-2 and your y-intercept, (0,b)=(0,4):
\n" ); document.write( "\"y=%28-2%29x%2B%284%29\"
\n" ); document.write( "\"highlight%28y=-2x%2B4%29\"
\n" ); document.write( "You said you know how to graph this, but just to be thorough:
\n" ); document.write( "Plot (0,4)
\n" ); document.write( "Form that point use your slope which is rise/run in this case -2/1 to plot another point. If you go down 2 and right 1 you should be plotting the point at (1,2)
\n" ); document.write( "Connect the two points and you should have a linbe that looks like this:
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-2x%2B4%29\"
\n" ); document.write( "Happy Calculating!!!
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