document.write( "Question 767554: I need help solving for x in this: ln (x+1) - ln (x) = 2. My options are 1/(e^2 - 1), x/(1-x), 1/x-1, e^2 - 1. Thanks!
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Algebra.Com's Answer #467682 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln%28x%2B1%29-ln%28x%29=ln%28%28x%2B1%29%2Fx%29\"$ because a rule of logarithms allows this.\r
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\n" ); document.write( "\n" ); document.write( "You then have $\"ln%28%28x%2B1%29%2Fx%29=2\"$
\n" ); document.write( " $\"e%5E2=%28x%2B1%29%2Fx\"$ and the left member is a constant.
\n" ); document.write( " $\"x%2Ae%5E2=x%2B1\"$
\n" ); document.write( " $\"-x%2Bx%2Ae%5E2=1\"$
\n" ); document.write( " $\"x%28-1%2Be%5E2%29=1\"$
\n" ); document.write( " $\"x=1%2F%28-1%2Be%5E2%29\"$
\n" ); document.write( "or equivalently
\n" ); document.write( " $\"x=1%2F%28e%5E2-1%29\"$ \n" ); document.write( "

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