document.write( "Question 767533: Sheila leaves on a long trip driving at a steady rate of 25 miles per hour. Her sister Allison leaves from the same location traveling to the same destination 2 hours later. She drives at a steady rate of 50 miles per hour. How long after Sheila leaves home will Allison catch up?
\n" ); document.write( "
\n" ); document.write( "I have tried this problem for approximately 3 hours. I'm in 9th grade and I'll be honest with you and say, this is a graded assignment. Thank you in advance for any help you can provide.\r
\n" ); document.write( "\n" ); document.write( "-Faith\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #467669 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
Distance = rate x time\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Sheila's rate = 25 mph
\n" ); document.write( "Sheila's time = t
\n" ); document.write( "Sheila's distance = 25t {distance = rate x time}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Allison's rate = 50mph
\n" ); document.write( "Allison's time = t - 2 {she started 2 hours later or lost two hours off of the starting time}
\n" ); document.write( "Allison's distance = 50(t - 2) = 50t - 100 {distance = rate x time}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "25t = 50(t - 2) {when Allison catches up with Sheila the distances are equal}
\n" ); document.write( "25t = 50t - 100 {used distributive property}
\n" ); document.write( "-25t = -100 {subtracted 50t from each side}
\n" ); document.write( "t = 4 {divided each side by -25}
\n" ); document.write( "{t corresponds with Sheila's time, which is what the question is asking for}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In 4 hours Allison will catch up with Sheila
\n" ); document.write( "{Your mistake was probably on Allison's time. You probably had t + 2.}
\n" ); document.write( "
For more help from me, visit:
www.algebrahouse.com

\n" ); document.write( "
\n" );