document.write( "Question 767522: jack is 6 years older than Jill. If four years ago Jack was 3 years less than twice Jill's age, how old is Jill now? \n" ); document.write( "
Algebra.Com's Answer #467663 by algebrahouse.com(1659)\"\" \"About 
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x = Jill's age now
\n" ); document.write( "x + 6 = Jack's age now {Jack is 6 years older than Jill}\r
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\n" ); document.write( "\n" ); document.write( "x - 4 = Jill's age 4 years ago
\n" ); document.write( "x + 2 = Jack's age 4 years ago {subtracted 4 from x + 6}\r
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\n" ); document.write( "\n" ); document.write( "2(x - 4) - 3 = x + 2 {four years ago, Jack's age was equal to 3 years less than twice Jill's age}
\n" ); document.write( "2x - 8 - 3 = x + 2 {used distributive property}
\n" ); document.write( "2x - 11 = x + 2 {combined like terms}
\n" ); document.write( "x = 13 {subtracted x and added 11 to each side}\r
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\n" ); document.write( "\n" ); document.write( "Jill is 13 now
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