document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66033>Question 66033</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>an incremental development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> simplify\r<BR>\n" );
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document.write( "6 - 7 times the square root of 3\r<BR>\n" );
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document.write( "DIVIDED BY\r<BR>\n" );
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document.write( "2 times the square root of 3 + 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46766 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simplify <BR>\n" );
document.write( "6 - 7 times the square root of 3 <BR>\n" );
document.write( "DIVIDED BY <BR>\n" );
document.write( "2 times the square root of 3 + 4\r<BR>\n" );
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document.write( "(6-7sqrt3)/(4+2sqrt3) \r<BR>\n" );
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document.write( "First, multiply both numerator and denominator by(4-2sqrt3), the conjugate of (4+2sqrt3).  This will get rid of the radical in the denominator.\r<BR>\n" );
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document.write( "NUMERATOR: (6-7sqrt3)(4-2sqrt3)=24-28sqrt3-12sqrt3+(14)(3)=66-40sqrt3<BR>\n" );
document.write( "DENOMINATOR(4+2sqrt3)/(4-2sqrt3)=16+8sqrt3-8sqrt3-(4)(3)=16-12=4\r<BR>\n" );
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document.write( "Now we have<BR>\n" );
document.write( "(66-40sqrt3)/4 divide numerator and denominator by 2 and we get:\r<BR>\n" );
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document.write( "(33-20sqrt3)/2\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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