document.write( "Question 767423: In a capture-recapture study, a biologist tagged and released 320 deer. A month later she captured 50 deer, 30 of which had tags. About how many deer were in the population?\r
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Algebra.Com's Answer #467650 by KMST(5328)\"\" \"About 
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Of the \"50\" deer re-captured, \"30\" had tags.
\n" ); document.write( "That means that \"30%2F50=3%2F5=0.6\"=60% of the re-captured deer had tags.
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\n" ); document.write( "Assuming the same proportion of the entire deer population has tags, the \"320\" deer initially tagged and released would be \"3%2F5\" of the total number of deer.
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\n" ); document.write( "If the entire deer population consists of \"x\" deer,
\n" ); document.write( "\"3%2F5=320%2Fx\" --> \"3x=320%2A5\" --> \"x=320%2A5%2F3\"
\n" ); document.write( "That calculates as \"320%2A5%2F3=1600%2F3=533%261%2F3\".
\n" ); document.write( "So the biologist will estimate it as \"x=533\"
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