document.write( "Question 66049: Please help me solve this and understand what I am doing thank you The graph of the equation $\"2x-y%2B8=0+\"$ crosses the x-axis at x=\r
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\n" ); document.write( "\n" ); document.write( "Do i first get the x by its self? $\"-y=2x-8\"$ then divide by -1? y=-2x=8?
\n" ); document.write( " $\"y=4\"$ then do I add 4 to find the answer for x? \n" ); document.write( "

Algebra.Com's Answer #46762 by tanimachatterjee(60) $\"\"$ $\"About$

You can put this solution on YOUR website!
2x-y+8=0 we know if a graph crosses the x-axis at any point then the y coordinate of the point must be 0
\n" ); document.write( " now if we put y=0 in the equation we have 2x-0+8=0
\n" ); document.write( " so 2x=-8
\n" ); document.write( " x=-4
\n" ); document.write( " therefore the point is (-4,0)
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