document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66037>Question 66037</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A sailboat can travel 60 miles, upstream in the same time it takes to travel 100 miles downstream. If the speed of the boast in still water is 20 miles per hour, what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46759 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60/(20-X)=100/(20+X)<BR>\n" );
document.write( "100(20-X)=60(20+X)<BR>\n" );
document.write( "2000-100X=1200+60X<BR>\n" );
document.write( "-100X-60X=1200-2000<BR>\n" );
document.write( "-160X=-800<BR>\n" );
document.write( "X=-800/-160<BR>\n" );
document.write( "X=5 MPH FOR THE CURRENT<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "60/(20-5)=100/(20+5)<BR>\n" );
document.write( "60/15=100/25<BR>\n" );
document.write( "4=4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );