document.write( "Question 767354: Sir/Madam,
\n" ); document.write( " A pleasant day! Please help me understand how to solve this problem. Find the value of k so that the equation is:
\n" ); document.write( "2x^2+kx-15=0, has one root of 3
\n" ); document.write( "Thank you very much for your help!
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Algebra.Com's Answer #467568 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+2x%5E2+%2B+k%2Ax+-+15+=+0+\"
\n" ); document.write( "I would use the quadratic formula:
\n" ); document.write( "\"+x+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+2+\"
\n" ); document.write( "\"+b+=+k+\"
\n" ); document.write( "\"+c+=+-15+\"
\n" ); document.write( "\"+x+=+%28-k+%2B-+sqrt%28+k%5E2+-+4%2A2%2A%28-15%29+%29%29+%2F+%282%2A2%29+\"
\n" ); document.write( "\"+x+=+%28-k+%2B-+sqrt%28+k%5E2+%2B+120+%29%29+%2F+4+\"
\n" ); document.write( "---------------------------------
\n" ); document.write( "If one of the roots is \"+3+\", I can say:
\n" ); document.write( "\"+3+=+%28-k+%2B+sqrt%28+k%5E2+%2B+120+%29%29+%2F+4+\"
\n" ); document.write( "\"+-k+%2B+sqrt%28+k%5E2+%2B+120+%29+=+12+\"
\n" ); document.write( "\"+sqrt%28+k%5E2+%2B+120+%29+=+k+%2B+12+\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"+k%5E2+%2B+120+=+k%5E2+%2B+24k+%2B+144+\"
\n" ); document.write( "\"+24k+=+-24+\"
\n" ); document.write( "\"+k+=+-1+\" answer
\n" ); document.write( "------------
\n" ); document.write( "I'll see if this works
\n" ); document.write( "\"+x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2+%2B+120+%29%29+%2F+4+\"
\n" ); document.write( "\"+x+=+%28+1+%2B-+sqrt%28+1+%2B+120+%29%29+%2F+4+\"
\n" ); document.write( "\"+x+=+%28+1+%2B+11+%29+%2F+4+\"
\n" ); document.write( "\"+x+=+12%2F4+\"
\n" ); document.write( "\"+x+=+3+\"
\n" ); document.write( "and, also.
\n" ); document.write( "\"+x+=+%28+1+-+sqrt%28+1+%2B+120+%29%29+%2F+4+\"
\n" ); document.write( "\"+x+=+%28+1+-+11+%29+%2F+4+\"
\n" ); document.write( "\"+x+=+-10%2F4+\"
\n" ); document.write( "\"+x+=+-5%2F2+\"
\n" ); document.write( "\"+2x+=+-5+\"
\n" ); document.write( "-------------
\n" ); document.write( "\"+%28+x-3+%29%2A%28+2x+%2B+5+%29+=+0+\"
\n" ); document.write( "\"+2x%5E2+%2B+%28-1%29%2Ax+-+15+=+0+\"
\n" ); document.write( "OK
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