document.write( "Question 66042This question is from textbook an incremental development
\n" ); document.write( ": use substitution to solve\r
\n" ); document.write( "\n" ); document.write( "2x + 3y = 9
\n" ); document.write( "5x - 2y = -25
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Algebra.Com's Answer #46753 by checkley71(8403)\"\" \"About 
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2X+3Y=9 NOW MULTIPLY THIS EQUATION BY 2 &
\n" ); document.write( "5X-2Y=-25 NOW MULTIPLY THIS EQUATION BY 3 WE CAN NOW ADD THESE 2 EQUATIONS THUS
\n" ); document.write( "4X+6Y=18
\n" ); document.write( "15X-6Y=-75 NOW ADD
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\n" ); document.write( "19X=-57
\n" ); document.write( "X=-57/19
\n" ); document.write( "X=-3 SOLUTION.
\n" ); document.write( "NOW REPLACE X BY -3 AND SOLVE FOR Y THUS
\n" ); document.write( "2*-3+3Y=9
\n" ); document.write( "-6+3Y=9
\n" ); document.write( "3Y=9+6
\n" ); document.write( "3Y=15
\n" ); document.write( "Y=15/3
\n" ); document.write( "Y=5
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