document.write( "Question 66042This question is from textbook an incremental development
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document.write( ": use substitution to solve\r
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document.write( "2x + 3y = 9
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document.write( "5x - 2y = -25 \n" );
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Algebra.Com's Answer #46753 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2X+3Y=9 NOW MULTIPLY THIS EQUATION BY 2 & \n" ); document.write( "5X-2Y=-25 NOW MULTIPLY THIS EQUATION BY 3 WE CAN NOW ADD THESE 2 EQUATIONS THUS \n" ); document.write( "4X+6Y=18 \n" ); document.write( "15X-6Y=-75 NOW ADD \n" ); document.write( "----------------------- \n" ); document.write( "19X=-57 \n" ); document.write( "X=-57/19 \n" ); document.write( "X=-3 SOLUTION. \n" ); document.write( "NOW REPLACE X BY -3 AND SOLVE FOR Y THUS \n" ); document.write( "2*-3+3Y=9 \n" ); document.write( "-6+3Y=9 \n" ); document.write( "3Y=9+6 \n" ); document.write( "3Y=15 \n" ); document.write( "Y=15/3 \n" ); document.write( "Y=5 \n" ); document.write( " |