document.write( "Question 767133: Write the equation of a line that is perpendicular to the given line and that passes through the given point.\r
\n" ); document.write( "\n" ); document.write( " y= 23x+9;(–6,5)\r
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\n" ); document.write( "\n" ); document.write( "a. y=−23x+1 c. y=23x+9
\n" ); document.write( "b. y=−3x+3 d. y=−3x−4 222
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Algebra.Com's Answer #467513 by mananth(16946)\"\" \"About 
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y= 23x+9;(–6,5)\r
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\n" ); document.write( "\n" ); document.write( "y= 23x+9;(–6,5)\r
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\n" ); document.write( "\n" ); document.write( "slope of line = 23\r
\n" ); document.write( "\n" ); document.write( "slope of line perpendicular to this line = -1/23\r
\n" ); document.write( "\n" ); document.write( "passes through (-6,5)\r
\n" ); document.write( "\n" ); document.write( "the general equation
\n" ); document.write( "(y-y1)= m(x-x1)\r
\n" ); document.write( "\n" ); document.write( "(y-5)=(-1/23)(x-(-6))\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 23\r
\n" ); document.write( "\n" ); document.write( "23(y-5)=-1(x+6)\r
\n" ); document.write( "\n" ); document.write( "23y-115=-x-6\r
\n" ); document.write( "\n" ); document.write( "23y+x=115+6\r
\n" ); document.write( "\n" ); document.write( "x+23y=121\r
\n" ); document.write( "\n" ); document.write( "write in the form required\r
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