document.write( "Question 767212: How long would it take a jogger traveling at 8 mph to catch up with a person walking 3 mph with a 2-hour head start? \n" ); document.write( "

Algebra.Com's Answer #467502 by josmiceli(19441) $\"\"$ $\"About$

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In 2 hrs, the walker has a head start of
\n" ); document.write( " $\"+d%5B1%5D+=+3%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+6+\"$ mi
\n" ); document.write( "--------------
\n" ); document.write( "Start a stopwatch when the jogger leaves,
\n" ); document.write( "let $\"+t+\"$ = the time in hrs on the stopwatch when
\n" ); document.write( "the jogger catches the walker
\n" ); document.write( "-------------
\n" ); document.write( "Let $\"+d+\"$ = the distance the jogger travels in miles
\n" ); document.write( "when the jogger catches the walker
\n" ); document.write( "-------------
\n" ); document.write( "Walker:
\n" ); document.write( "(1) $\"+d+-+6+=+3t+\"$
\n" ); document.write( "Jogger:
\n" ); document.write( "(2) $\"+d+=+8t+\"$
\n" ); document.write( "-------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) $\"+8t+-+6+=+3t+\"$
\n" ); document.write( "(1) $\"+5t+=+6+\"$
\n" ); document.write( "(1) $\"+t+=+6%2F5+\"$
\n" ); document.write( "(1) $\"+t+=+1.2+\"$
\n" ); document.write( "and $\"+.2%2A60+=+12+\"$
\n" ); document.write( "It will take the jogger 1 hr and 12 min to catch the walker
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+-+6+=+3%2A1.2+\"$
\n" ); document.write( "(1) $\"+d+=+6+%2B+3.6+\"$
\n" ); document.write( "(1) $\"+d+=+9.6+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+=+8t+\"$
\n" ); document.write( "(2) $\"+d+=+8%2A1.2+\"$
\n" ); document.write( "(2) $\"+d+=+9.6+\"$ mi
\n" ); document.write( "OK\r
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