document.write( "Question 767129: Please help me to find the product of 2^2007 and 5^2000 and then calculate the sum of the digits of the answer.Eric arrived at an answer of 11.is he correct? \n" ); document.write( "
Algebra.Com's Answer #467437 by Edwin McCravy(20054)\"\" \"About 
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document.write( "22007×52000 =\r\n" );
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document.write( "22000+7×52000 =\r\n" );
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document.write( "(22000×27)×52000 =\r\n" );
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document.write( "22000×27×52000 =\r\n" );
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document.write( "22000×52000×27 =\r\n" );
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document.write( "(22000×52000)×27 =\r\n" );
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document.write( "(2×5)2000×128 =\r\n" );
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document.write( "102000×128 =\r\n" );
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document.write( "128×102000 =\r\n" );
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document.write( "(1.28×102)×22000\r\n" );
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document.write( "1.28×(102×22000)\r\n" );
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document.write( "1.28×102002\r\n" );
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document.write( "So the answer is 1280000000...0  with 2000 zeros.\r\n" );
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document.write( "So the sum of the digits is 1+2+8 = 11\r\n" );
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document.write( "Yes 11 is correct.\r\n" );
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document.write( "Edwin

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