document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766971>Question 766971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the gradient of the line that goes through (-3,-5) and (-1,-7). and hence, find the equation of this traight line. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467371 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using equation: y2 - y1/x2 - x1<BR>\n" );
document.write( "-7 -(-5)/-1 - (-3)<BR>\n" );
document.write( "-2/2  =  -1 (gradient)<BR>\n" );
document.write( "Using equation: <BR>\n" );
document.write( "y - b = m(x - a)<BR>\n" );
document.write( "a = -5 b = -3 m = -1<BR>\n" );
document.write( "y - (-3)= -1(x - (-5))<BR>\n" );
document.write( "y + 3 = -1(x + 5)<BR>\n" );
document.write( "y + 3 = -x - 5<BR>\n" );
document.write( "y = -x - 5 - 3<BR>\n" );
document.write( "y = -x - 8<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );