document.write( "Question 766991: A man is 4 times as old as her daughter. After 16 years, he will be twice as old as his daughter. find daughter's age. \n" ); document.write( "
Algebra.Com's Answer #467355 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = daughter's age now \n" ); document.write( "4x = man's age now\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 16 = daughter's age in 16 years \n" ); document.write( "4x + 16 = man's age in 16 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(x + 16) = 4x + 16 {in 16 years he will be twice as old as his daughter} \n" ); document.write( "2x + 32 = 4x + 16 {used distributive property} \n" ); document.write( "2x = 16 {subtracted 2x and 16 from each side} \n" ); document.write( "x = 8 {divided each side by 2}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "daughter is 8 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |