document.write( "Question 766973: y=(x+4)^2+3 \n" ); document.write( "
Algebra.Com's Answer #467353 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Graph: \n" ); document.write( "y=(x+4)^2+3 \n" ); document.write( "by using techniques of \"transformations\". \n" ); document.write( ". \n" ); document.write( "Starting point: \n" ); document.write( "y = x^2 \n" ); document.write( "This is simply a parabola that opens upwards and the vertex is at the origin. \n" ); document.write( ". \n" ); document.write( "y = (x+4)^2 \n" ); document.write( "The above \"horizontally shifts\" the \"starting point\" to the LEFT 4 units. That is, the vertex is now at (-4,0). \n" ); document.write( ". \n" ); document.write( "Finally, \n" ); document.write( "y = (x+4)^2 + 3 \n" ); document.write( "Shifts it vertically UP three units. That is, the vertex is now at (-4,3). \n" ); document.write( " |