document.write( "Question 766973: y=(x+4)^2+3 \n" ); document.write( "
Algebra.Com's Answer #467353 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Graph:
\n" ); document.write( "y=(x+4)^2+3
\n" ); document.write( "by using techniques of \"transformations\".
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\n" ); document.write( "Starting point:
\n" ); document.write( "y = x^2
\n" ); document.write( "This is simply a parabola that opens upwards and the vertex is at the origin.
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\n" ); document.write( "y = (x+4)^2
\n" ); document.write( "The above \"horizontally shifts\" the \"starting point\" to the LEFT 4 units. That is, the vertex is now at (-4,0).
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\n" ); document.write( "Finally,
\n" ); document.write( "y = (x+4)^2 + 3
\n" ); document.write( "Shifts it vertically UP three units. That is, the vertex is now at (-4,3).
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