document.write( "Question 766905: Meg rowed her boat upstream a distance of 91 mi and then rowed back to the starting point. The total time of the trip was 20 hours. If the rate of the current was 3 mph, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #467341 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed x mph \n" ); document.write( "current speed 3 mph \n" ); document.write( " \n" ); document.write( "against current x- 3 mph \n" ); document.write( "with current x+ 3 mph \n" ); document.write( " \n" ); document.write( "Distance= 91 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 20 hours \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "91 /( x + 3 ) + 91 /(x - 3 ) = 20 \n" ); document.write( " \n" ); document.write( "LCD = (x - 3 ) ( x + 3 ) \n" ); document.write( "91 *( x - 3 ) + 91 (x + 3 ) = 20 (x^2 - 9 ) \n" ); document.write( "91 x - -273 + 91 x + 273 = 20 ( x ^2 - 9 ) \n" ); document.write( "182 x = 20 x ^2 -180 \n" ); document.write( "20 x ^2 - -182 x - 180 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " iiiii \n" ); document.write( "a= 20 , b= -182 , c= -180 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 33124 + 14400 \n" ); document.write( "b^2-4ac= 47524 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 182 + 218 )/ 40 \n" ); document.write( "x1= 10.00 \n" ); document.write( " \n" ); document.write( "x2=( 182 -218 ) / 40 \n" ); document.write( "x2= -0.90 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 10 mph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |