document.write( "Question 766924: find the exact value by using a sum or difference identity\r
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document.write( "tan(pi/12) \n" );
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Algebra.Com's Answer #467334 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the exact value by using a sum or difference identity \n" ); document.write( "tan(pi/12) \n" ); document.write( "-- \n" ); document.write( "1/12 = 1/3 - 1/4 \n" ); document.write( "---- \n" ); document.write( "tan(pi/12) = tan[pi/3 - pi/4) = [tan(pi/3)-tan(pi/4)]/[1+tan(pi/3)tan(pi/4] \n" ); document.write( "------ \n" ); document.write( "= [sqrt(3)-1]/[1+sqrt(3)] \n" ); document.write( "------ \n" ); document.write( "={(sqrt(3)-1)(sqrt(3)-1)]/[sqrt(3)+1]^2 \n" ); document.write( "---- \n" ); document.write( "= [3-2sqrt(3)+1]/[3-1] \n" ); document.write( "------------------------------ \n" ); document.write( "= [4-2sqrt(3)]/2 \n" ); document.write( "----- \n" ); document.write( "= 2-sqrt(3) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |