document.write( "Question 766924: find the exact value by using a sum or difference identity\r
\n" ); document.write( "\n" ); document.write( "tan(pi/12)
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Algebra.Com's Answer #467334 by stanbon(75887)\"\" \"About 
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find the exact value by using a sum or difference identity
\n" ); document.write( "tan(pi/12)
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\n" ); document.write( "1/12 = 1/3 - 1/4
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\n" ); document.write( "tan(pi/12) = tan[pi/3 - pi/4) = [tan(pi/3)-tan(pi/4)]/[1+tan(pi/3)tan(pi/4]
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\n" ); document.write( "= [sqrt(3)-1]/[1+sqrt(3)]
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\n" ); document.write( "={(sqrt(3)-1)(sqrt(3)-1)]/[sqrt(3)+1]^2
\n" ); document.write( "----
\n" ); document.write( "= [3-2sqrt(3)+1]/[3-1]
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\n" ); document.write( "= [4-2sqrt(3)]/2
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\n" ); document.write( "= 2-sqrt(3)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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