document.write( "Question 766752: Please please please help me :'(\r
\n" ); document.write( "\n" ); document.write( "x9 + 1
\n" ); document.write( "A (x + 1)(x2 - x + 1)(x6 - x3 + 1)
\n" ); document.write( "B(x3 + 1)(x6 + 1)
\n" ); document.write( "C(x + 1)(x2 - x + 1)(x3-1)2
\n" ); document.write( "D(x + 1)3(x2 - x + 1)3
\n" ); document.write( "E (x3 + 1)(x6 - x3 + 1)
\n" ); document.write( "F cannot be factored\r
\n" ); document.write( "\n" ); document.write( "2x9 + 16
\n" ); document.write( "A 2(x - 2)(x8 - 2x4 + 4)
\n" ); document.write( "B2(x3 - 2)(x6 - 2x3 + 2)
\n" ); document.write( "C(2x3 + 2)(x6 - 2x3 - 4)
\n" ); document.write( "D2(x3 + 2)(x6 - 2x3 + 4)
\n" ); document.write( "E 2x3(x6 + 2x3 + 4)
\n" ); document.write( "F cannot be factored
\n" ); document.write( "

Algebra.Com's Answer #467332 by ankor@dixie-net.com(22740)\"\" \"About 
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\n" ); document.write( "x^9 + 1
\n" ); document.write( "Can be factored as the \"sum of cubes\" which is x^3 + y^3 = (x + y)(x^2- xy + y^2)
\n" ); document.write( "so we have
\n" ); document.write( "x^9 + 1 = (x^3 + 1)(x^6 - x^3 + 1)
\n" ); document.write( ":
\n" ); document.write( "2x^9 + 16
\n" ); document.write( "Factor out 2, then factor as the sum of cubes
\n" ); document.write( "2(x^9 + 8) = 2(x^3 + 2)(x^6 - 2x^3 + 4)
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