document.write( "Question 65980: Martina leaves home at 9 A.M., bicycling at a rate of
\n" ); document.write( "24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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Algebra.Com's Answer #46728 by uma(370)\"\" \"About 
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Speed of Martina = 24 mph
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\n" ); document.write( "==> at 11 A.M., Martina is 48 miles away from John.\r
\n" ); document.write( "\n" ); document.write( "Speed of John = 48 mph\r
\n" ); document.write( "\n" ); document.write( "Let us say the they both meet after x hrs after John's departure.\r
\n" ); document.write( "\n" ); document.write( "Distance travelled by Martina in x hrs = 24x + 48\r
\n" ); document.write( "\n" ); document.write( "Distance travelled by John in x hrs = 48x\r
\n" ); document.write( "\n" ); document.write( "As they meet , they would have travelled the same distance.\r
\n" ); document.write( "\n" ); document.write( "==> 48x = 24x + 48
\n" ); document.write( "==> 48x - 24x = 48
\n" ); document.write( "==> 24x = 48
\n" ); document.write( "==> 24x/24 = 48/24
\n" ); document.write( "==> x = 2\r
\n" ); document.write( "\n" ); document.write( "==> they meet after 2hrs after John's departure.
\n" ); document.write( "==> they meet at 11 A.M., + 2hrs
\n" ); document.write( " at 1 P.M\r
\n" ); document.write( "\n" ); document.write( "Thus John catches up with Martina at 1 P.M\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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