document.write( "Question 766779: Maureen sets off on a walk at 6km/h. Ten minutes later, her brother John sets off after her on his bicycle at 15 km/h. How far must john go to catch up with Maureen? \n" ); document.write( "
Algebra.Com's Answer #467273 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Maureen traveled a distance already in ten minutes before John began. Maureen already went \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Maureen and John then both travel for some equal time which we not yet know; and their total distances become equal. Let h be the amount of time in hours that they travel simultaneously. Make a data table:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SIBLING__________speed_________time___________distance \n" ); document.write( "Maureen__________6_____________h+1/6___________(__) \n" ); document.write( "John_____________15____________h______________(__)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What can we do about the unknown distance for them? \n" ); document.write( "r*t=d or in the variables chosen, r*h=d. \n" ); document.write( "10 minutes is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SIBLING__________speed_________time___________distance \n" ); document.write( "Maureen__________6_____________ \n" ); document.write( "John_____________15____________h______________ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When John reaches Maureen, they have both gone equal distances, so the equation is to equate their distance expressions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |