document.write( "Question 766779: Maureen sets off on a walk at 6km/h. Ten minutes later, her brother John sets off after her on his bicycle at 15 km/h. How far must john go to catch up with Maureen? \n" ); document.write( "
Algebra.Com's Answer #467273 by josgarithmetic(39617)\"\" \"About 
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Maureen traveled a distance already in ten minutes before John began. Maureen already went \"6%2A%2810%2F60%29\" km. This is 1 km.\r
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\n" ); document.write( "\n" ); document.write( "Maureen and John then both travel for some equal time which we not yet know; and their total distances become equal. Let h be the amount of time in hours that they travel simultaneously. Make a data table:\r
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\n" ); document.write( "\n" ); document.write( "SIBLING__________speed_________time___________distance
\n" ); document.write( "Maureen__________6_____________h+1/6___________(__)
\n" ); document.write( "John_____________15____________h______________(__)\r
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\n" ); document.write( "\n" ); document.write( "What can we do about the unknown distance for them?
\n" ); document.write( "r*t=d or in the variables chosen, r*h=d.
\n" ); document.write( "10 minutes is \"1%2F6\" hour.\r
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\n" ); document.write( "\n" ); document.write( "SIBLING__________speed_________time___________distance
\n" ); document.write( "Maureen__________6_____________\"h%2B1%2F6\"___________\"%286%28h%2B1%2F6%29%29\"
\n" ); document.write( "John_____________15____________h______________\"%2815h%29\"\r
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\n" ); document.write( "\n" ); document.write( "When John reaches Maureen, they have both gone equal distances, so the equation is to equate their distance expressions.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%286%28h%2B1%2F6%29=15h%29\" and a reminder, h is in hours. Solve for h and then distance can easily be computed.
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