document.write( "Question 65979: The length of a rectangular playing field is 5 ft less than twice its width.
\n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field
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Algebra.Com's Answer #46727 by uma(370)\"\" \"About 
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Let the width of the field be x ft.
\n" ); document.write( "So length = (2x-5) ft\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2[ length + width]
\n" ); document.write( "==> 2[2x-5+x] = 230
\n" ); document.write( "==> 2{3x-5} = 230
\n" ); document.write( "==> 6x - 10 = 230
\n" ); document.write( "==> 6x - 10 + 10 = 230 + 10
\n" ); document.write( "==> 6x = 240
\n" ); document.write( "==> 6x/6 = 240/6
\n" ); document.write( "==> x = 40\r
\n" ); document.write( "\n" ); document.write( "Thus the width of the field = 40 ft.
\n" ); document.write( "Length = 2x-5
\n" ); document.write( " = 2*40 - 5
\n" ); document.write( " = 80 - 5
\n" ); document.write( " = 75
\n" ); document.write( "Width = 40 ft and length = 75 ft\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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