document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65977>Question 65977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one angle of a trianlge is five times that of a second angle, and the measure of an exterior angle at the third vertex is 120 degrees. What is the measure of each angle of the triangle?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46726 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the second angle of the triangle be x deg.\r<BR>\n" );
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document.write( "so the first angle measures = 5x deg.\r<BR>\n" );
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document.write( "measure of the exterior angle at the third vertex = 120 deg\r<BR>\n" );
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document.write( "The exterior angle = sum of interior opposite angles.\r<BR>\n" );
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document.write( "==> 120 = x + 5x<BR>\n" );
document.write( "==> 120 = 6x<BR>\n" );
document.write( "==> 120/6 = 6x/6<BR>\n" );
document.write( "==> 20 = x\r<BR>\n" );
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document.write( "Therefore the angles of the triangle are 20 deg, 100 deg and 60 deg[as the sum is always = 180 deg]\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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