document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766799>Question 766799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 3 years old as his son. In 12 years he will be twice as old as his son. How old is the fathr and son?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467239 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Father is 3 times his son's age<BR>\n" );
document.write( "f = 3d<BR>\n" );
document.write( "In 12 years the father will be twice as old as his son.<BR>\n" );
document.write( "f + 12 = 2(d + 12)<BR>\n" );
document.write( "Substitute 3d for f in equation.<BR>\n" );
document.write( "3d + 12 = 2(d + 12)<BR>\n" );
document.write( "3d + 12 = 2d + 24<BR>\n" );
document.write( " d = 12 (Son's age)<BR>\n" );
document.write( "Substitute d = 12 into f = 3d<BR>\n" );
document.write( "f = 3(12)<BR>\n" );
document.write( "f = 36<BR>\n" );
document.write( "So, father's age = 36<BR>\n" );
document.write( "son's age = 12<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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