document.write( "Question 65968: Find three consecutive odd integers such that twice the second is 5 more than the last ? \n" ); document.write( "

Algebra.Com's Answer #46719 by venugopalramana(3286) $\"\"$ $\"About$

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Find three consecutive odd integers such that twice the second is 5 more than the last ?Find three consecutive odd integers such that twice the second
\n" ); document.write( "is 5 more than the last ?
\n" ); document.write( "ANY INTEGER IS N
\n" ); document.write( "ANY EVEN INTEGER IS 2N
\n" ); document.write( "ANY ODD INTEGER IS 2N-1
\n" ); document.write( "3 CONSECUTIVE ODD INTEGERS ARE
\n" ); document.write( "2N-1,2N-1+2=2N+1,2N-1+2+2=2N+3
\n" ); document.write( "TWICE THE SECOND = 2(2N+1)=4N+2
\n" ); document.write( "5 MORE THAN THE LAST = 2N+3+5=2N+8....HENCE
\n" ); document.write( "4N+2=2N+8
\n" ); document.write( "4N-2N=8-2=6
\n" ); document.write( "2N=6
\n" ); document.write( "N=3.
\n" ); document.write( "HENCE THE 3 NUMBERS ARE
\n" ); document.write( "2N-1=2*3-1=5
\n" ); document.write( "2N+1=2*3+1=7
\n" ); document.write( "2N+3=2*3+3=9 \n" ); document.write( "

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