document.write( "Question 766567: The ratio of the ages of A and B ten years ago was 3:5. If the ratio of their present ages is 2:3 how old is B today? \n" ); document.write( "

Algebra.Com's Answer #467132 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The ratio of the ages of A and B ten years ago was 3:5.
\n" ); document.write( " If the ratio of their present ages is 2:3
\n" ); document.write( " how old is B today?
\n" ); document.write( ":
\n" ); document.write( "Let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "2x = age of A
\n" ); document.write( "3x = age of B
\n" ); document.write( ":
\n" ); document.write( " $\"%282x-10%29%2F%283x-10%29\"$ = $\"3%2F5\"$
\n" ); document.write( "cross multiply
\n" ); document.write( "5(2x-10) = 3(3x-10)
\n" ); document.write( "10x-50 = 9x-30
\n" ); document.write( "10x - 9x = -30 + 50
\n" ); document.write( "x = 20 is the multiplier
\n" ); document.write( ":
\n" ); document.write( "3*20 = 60 is B's age
\n" ); document.write( " \n" ); document.write( "

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