document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65956>Question 65956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular playing field is 5 ft less than twice its width.<BR>\n" );
document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46709 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \"l\" be the lenght of the field \r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "\"b\" be the breadth of the rectangular field. \r<BR>\n" );
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document.write( "Given that the perimeter of the field is 230ft.\r<BR>\n" );
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document.write( "Also, given that the lenght of the field is 5ft less than twice its width. \r<BR>\n" );
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document.write( "Therefore, \r<BR>\n" );
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document.write( "l = 2b - 5   and b = b \r<BR>\n" );
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document.write( "The perimeter is given by 2l + 2b\r<BR>\n" );
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document.write( "Hence, 2l + 2b = 230 \r<BR>\n" );
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document.write( "2(2b - 5) + 2b = 230 \r<BR>\n" );
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document.write( "4b - 10 + 2b = 230 \r<BR>\n" );
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document.write( "Adding like terms, we get: \r<BR>\n" );
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document.write( "6b - 10 = 230 \r<BR>\n" );
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document.write( "6b = 230 + 10 \r<BR>\n" );
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document.write( "6b = 240 \r<BR>\n" );
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document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=240%2F6 ALIGN=MIDDLE  ALT=\"240%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "==> b = 40 \r<BR>\n" );
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document.write( "Now, substitute this value in the equation for l. We get: \r<BR>\n" );
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document.write( "l = 2b - 5 \r<BR>\n" );
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document.write( "l = 2(40) - 5 \r<BR>\n" );
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document.write( "l = 80 - 5 \r<BR>\n" );
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document.write( "l = 75 \r<BR>\n" );
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document.write( "Hence, the solution.\r<BR>\n" );
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