document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65961>Question 65961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The directions are use the substitution method to solve the Linear system.<BR>\n" );
document.write( "The Problem is: One share of stock A is worth 3 1/2 shares of stock B. If the total value of the stock is $9,000, how much was invested in each company? The equations that I have come up wich are A=3 1/2B and A+B=9,000 i don't know what to do next or if my equations are right. If you have the time please help me figure this problem out. I've worked on it for days and i just can't get it. Thanks.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46706 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "You are right on target on this one!!!!!! Good work!!!!!You have gotten past the hard part.  All that's left to do is solve:\r<BR>\n" );
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document.write( "(1) A+B=9000<BR>\n" );
document.write( "(2)A=(3.5)B\r<BR>\n" );
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document.write( "Substitute (2) in (1) and we have:\r<BR>\n" );
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document.write( "(3.5)B+B=9000<BR>\n" );
document.write( "(4.5)B=9000<BR>\n" );
document.write( "B=$2000 Total value of Stock B \r<BR>\n" );
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document.write( "Substitute B=$2000 in (1):<BR>\n" );
document.write( "A=9000-2000=$7000 Total value of stock A\r<BR>\n" );
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document.write( "ck<BR>\n" );
document.write( "7000=(3.5)2000<BR>\n" );
document.write( "and<BR>\n" );
document.write( "7000+2000=9000\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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