document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766592>Question 766592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a lenght which is 5cm less than twice its breadth. if the length is decreased by 5 cm and breadth is increased by 2 cm.the perimeter of the resulting rectangle will be 74.find the length and breadth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #467052 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=467052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Breadth = x<BR>\n" );
document.write( "Length = 2x - 5<BR>\n" );
document.write( "Then the length is decreased by 5<BR>\n" );
document.write( "= 2x - 10<BR>\n" );
document.write( "The breadth is increased by 2<BR>\n" );
document.write( "= x + 2<BR>\n" );
document.write( "Perimeter = 2*breadth + 2*length<BR>\n" );
document.write( "74 = 2*(x + 2)+ 2*(2x - 10)<BR>\n" );
document.write( "74 = 2x + 4 + 4x - 20<BR>\n" );
document.write( "74 = 6x - 16<BR>\n" );
document.write( "6x = 74 + 16<BR>\n" );
document.write( "6x = 90<BR>\n" );
document.write( " x = 15 cm<BR>\n" );
document.write( "Breadth = 15cm<BR>\n" );
document.write( "Length = 25cm<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );