document.write( "Question 766564: a sphere has a surface area of 64 p.i. find the surface area of the largest cube contained in the sphere
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Algebra.Com's Answer #467022 by stanbon(75887)\"\" \"About 
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a sphere has a surface area of 64 p.i. find the surface area of the largest cube contained in the sphere
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\n" ); document.write( "SA = 4*pi*r^2 = 64
\n" ); document.write( "r^2 = 16pi
\n" ); document.write( "r = 4sqrt(pi)
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\n" ); document.write( "Diagonal of the cube = 8*sqrt(pi)
\n" ); document.write( "Diagonal of the base of the cube = (8sqrt(pi))/sqrt(2) = 8sqrt(pi/2)
\n" ); document.write( "Edge of the cube = (8sqrt(pi/2))/sqrt(2) = 8sqrt(pi/4) = 4sqrt(pi)
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\n" ); document.write( "Surface area of the cube = 6(4sqrt(pi))^2 = 6(16pi) = 96pi sq units
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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