document.write( "Question 757927: 9x^2-16y^2=144 \n" ); document.write( "
Algebra.Com's Answer #466990 by DSMLMD(16)\"\" \"About 
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9x^2-16y^2=144
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\n" ); document.write( "divide 144 to the two sides we get:
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\n" ); document.write( "x^2/16 - y^2/9 = 1
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\n" ); document.write( "the equation can be written as:
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\n" ); document.write( "(x-0)^2/16 - (y-0)^2/9 = 1
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\n" ); document.write( "we get:
\n" ); document.write( "h=0
\n" ); document.write( "k=0
\n" ); document.write( "a^2 = 16 -> a = 4
\n" ); document.write( "b^2 = 9 -> b = 3
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\n" ); document.write( "now, we must find c
\n" ); document.write( "c^2 = a^2 + b^2
\n" ); document.write( "c^2 = 16 + 9
\n" ); document.write( "c^2 = 25
\n" ); document.write( "c = 5
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\n" ); document.write( "foci:
\n" ); document.write( "(h±c,k)
\n" ); document.write( "(0±5,0)
\n" ); document.write( "(-5,0) and (5,0)
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\n" ); document.write( "vertices:
\n" ); document.write( "(h±a,k)
\n" ); document.write( "(0±4,0)
\n" ); document.write( "(-4,0) and (4,0)
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\n" ); document.write( "center
\n" ); document.write( "(h,k)
\n" ); document.write( "(0,0)
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\n" ); document.write( "asymptotes
\n" ); document.write( "y=±b/a(x-h)+k
\n" ); document.write( "y=±3/4(x-0)+0
\n" ); document.write( "y=±3x/4
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\n" ); document.write( "it's hyperbola \n" ); document.write( "
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