document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766533>Question 766533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> James needs to mix a 10% alcohol solution with a 60% alcohol solution to create 100 millileters of a 20% solution. How many millileters of each solution must James use?\r<BR>\n" );
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document.write( "A) Write an equation using the information as it is given above that can be used to solve this problem. Use  as your variable to represent the quantity of 10% alcohol solution.\r<BR>\n" );
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document.write( "Equation:       \r<BR>\n" );
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document.write( "B) Answer: James must mix HOW MANY millileters of 10% solution and HOW MANY millileters of 60% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466974 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have 2 equations:<BR>\n" );
document.write( "x + y = 100<BR>\n" );
document.write( ".1x + .6y = 20\r<BR>\n" );
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document.write( "x is the number of milliliters of 10% solution.<BR>\n" );
document.write( "y is the number of milliliters of 60% solution.\r<BR>\n" );
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document.write( "100 milliliters of 20% solution yields 20 milliliters of alcohol.\r<BR>\n" );
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document.write( "solve these 2 equations simultaneously to get your answer.<BR>\n" );
document.write( "use the elimination method as shown below:\r<BR>\n" );
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document.write( "x + y = 100 (equation 1)<BR>\n" );
document.write( ".1x + .6y = 20 (equation 2)\r<BR>\n" );
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document.write( "multiply equation 2 by 10 to get equation 3 as shown below:<BR>\n" );
document.write( "x + 6y = 200 (equation 3)\r<BR>\n" );
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document.write( "subtract equation 1 from equation 3 as shown below:\r<BR>\n" );
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document.write( "x + 6y = 200 (e3)<BR>\n" );
document.write( "x + y = 100 (e4)\r<BR>\n" );
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document.write( "result of the subtraction is:<BR>\n" );
document.write( "5y = 100 (equation 5)<BR>\n" );
document.write( "divide both sides of this equation by 5 to get:<BR>\n" );
document.write( "y = 20\r<BR>\n" );
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document.write( "substitute for y in equation 1 to get:<BR>\n" );
document.write( "x + y = 100 becomes:<BR>\n" );
document.write( "x + 20 = 100<BR>\n" );
document.write( "solve for x to get:<BR>\n" );
document.write( "x = 80\r<BR>\n" );
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document.write( "your solution is :<BR>\n" );
document.write( "x = 80<BR>\n" );
document.write( "y = 20\r<BR>\n" );
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document.write( "you need 80 milliliters of 10% solution and 20 liters of 60% solution to get 100 milliliters of 20% solution.\r<BR>\n" );
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document.write( "x + y = 80 + 20 = 100 ml of solution<BR>\n" );
document.write( ".1x + .6y = .1(80) + .6(20) = 8 + 12 = 20 ml of alcohol\r<BR>\n" );
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document.write( " </SPAN>\n" );
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