document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65941>Question 65941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you graph the equation y=x^2-6x+6??? plllzz help....thannk u very much ^^\r<BR>\n" );
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document.write( "this is from a midyear exam in january 2004 in bronx science </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46695 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do you graph the equation y=x^2-6x+6<BR>\n" );
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document.write( "One way: You could plot points by giving values for <BR>\n" );
document.write( "x and solving for y.<BR>\n" );
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document.write( "Another way:<BR>\n" );
document.write( "You might know the vertex is at x=-b/2a=6/2=3<BR>\n" );
document.write( "Then find f(3)=9-18+6=-3<BR>\n" );
document.write( "That gives you the vertex at (3,-3)<BR>\n" );
document.write( "You can see that f(0)=6; that gives you the y-intercept.<BR>\n" );
document.write( "You could find the x-intercepts by using the quadratic formula:<BR>\n" );
document.write( "x=[6+-sqrt(36-4*6)]/2<BR>\n" );
document.write( "x=[6+-sqrt(12)]/2<BR>\n" );
document.write( "x= 3+sqrt3 or x=3-sqrt3<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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