document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766389>Question 766389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is x years old which his son is y years old. the sum of their ages is twice the difference of their ages. if the product of their ages is 675, find the age of the man </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466940 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let age of man be x years and age of son is y years\r<BR>\n" );
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document.write( "x + y = 2 (x - y) <BR>\n" );
document.write( "x + y = 2x - 2y<BR>\n" );
document.write( "3y - x = 0   .....(1)\r<BR>\n" );
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document.write( "x*y = 675 ...(2)\r<BR>\n" );
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document.write( "replace value of y from equation (2) into (1)\r<BR>\n" );
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document.write( "3*(675/x) - x = 0<BR>\n" );
document.write( "2025 - x^2 = 0\r<BR>\n" );
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document.write( "x^2 = 2025<BR>\n" );
document.write( "x = sqrt(2025) = 45\r<BR>\n" );
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document.write( "age of man is 45 years<BR>\n" );
document.write( "age of son is 15 years<BR>\n" );
document.write( " </SPAN>\n" );
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