document.write( "Question 766460: 28x - 140 I have six steps to do this problem
\n" ); document.write( "1. move the constant term to the right side of the equation
\n" ); document.write( "2. multiply each term in the equation by four times the coefficient of the x to the second power term
\n" ); document.write( "3. square the coefficient of the original x term and add it to both sides of the equation
\n" ); document.write( "4. take the square root of both sides
\n" ); document.write( "5. set the left side of the equation equal to the positive square root of the number on the right side and solve for x
\n" ); document.write( "6. set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x
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Algebra.Com's Answer #466931 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"28x+-+140+=0\"\r
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\n" ); document.write( "\n" ); document.write( "1. move the constant term to the right side of the equation\r
\n" ); document.write( "\n" ); document.write( "\"28x+=140+\"\r
\n" ); document.write( "\n" ); document.write( "2. multiply each term in the equation by four times the coefficient of the \"x\" to
\n" ); document.write( "the second power term\r
\n" ); document.write( "\n" ); document.write( "\"28%2A28%5E2x+=140+%2A28%5E2\"\r
\n" ); document.write( "\n" ); document.write( "3. square the coefficient of the original \"x\" term and add it to both sides
\n" ); document.write( "of the equation\r
\n" ); document.write( "\n" ); document.write( "\"28%2A28%5E2x+%2B28%5E2=140+%2A28%5E2%2B28%5E2\"\r
\n" ); document.write( "\n" ); document.write( "4. take the square root of both sides\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%2828%2A28%5E2x+%2B28%5E2%29=sqrt%28140+%2A28%5E2%2B28%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "5. set the left side of the equation equal to the positive square root of
\n" ); document.write( "the number on the right side and solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%2828%2A28%5E2x+%2B28%5E2%29=sqrt%28110544%29\"\r
\n" ); document.write( "\n" ); document.write( "\"28%2A28%5E2x+%2B28%5E2=110544\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+%2B784=110544\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+=110544-784\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+=109760\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=109760%2F21952\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=5\"\r
\n" ); document.write( "\n" ); document.write( "6. set the left side of the equation equal to the negative square root of
\n" ); document.write( "the number on the right side of the equation and solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%2828%2A28%5E2x+%2B28%5E2%29=sqrt%28110544%29\"\r
\n" ); document.write( "\n" ); document.write( "\"28%2A28%5E2x+%2B28%5E2=-110544\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+%2B784=-110544\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+=-110544-784\"\r
\n" ); document.write( "\n" ); document.write( "\"21952x+=-109760\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=-109760%2F21952\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=-5\"\r
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