document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766456>Question 766456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> fill in the blank make the expression a perfect square v^2 - 6v +? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466907 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> fill in the blank make the expression a perfect square v^2 - 6v +?<BR>\n" );
document.write( "take half the coefficient of the v term and square it.<BR>\n" );
document.write( "add it to the expression then subtract the same amount to keep the expression in balance<BR>\n" );
document.write( "(v^2 - 6v +9)-9=(v-3)^2-9<BR>\n" );
document.write( "if the sign of the middle term is positive,<BR>\n" );
document.write( "(v^2 + 6v +9)-9=(v+3)^2-9 </SPAN>\n" );
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