document.write( "Question 766400: d+e-f=10
\n" ); document.write( "e=f+d+2
\n" ); document.write( "f=2e-7\r
\n" ); document.write( "\n" ); document.write( "Solve with substitution
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #466891 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
First using the f= equation, having only two of the variables, to substitute into the first two equations may be easiest.\r
\n" ); document.write( "\n" ); document.write( "d+e+(2e-7)=10 and e=(2e-7)+d+2
\n" ); document.write( "d+3e-7=10 and e=2e+d-5
\n" ); document.write( "d+3e=17 and 0=e+d-5
\n" ); document.write( "d=17-3e.
\n" ); document.write( "Let's use this formula for d and substitute into the 0= equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "0=e+(17-3e)-5
\n" ); document.write( "0=-2e+17-5
\n" ); document.write( "-2e=5-17
\n" ); document.write( "2e=17-5=15
\n" ); document.write( "\"e=15%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Maybe now would be easiest to find f.
\n" ); document.write( "f=2(e)-7 and you just found e...\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "continue...?
\n" ); document.write( "
\n" );