document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=725092>Question 725092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am having trouble solving: find real numbers x and y if:<BR>\n" );
document.write( "(x+i)(3-iy)= 1+13i<BR>\n" );
document.write( "i have done:<BR>\n" );
document.write( " 3x- xyi +3i +y= 1+13i<BR>\n" );
document.write( "3x+y=1        -xy+3=13<BR>\n" );
document.write( "x+y=1/3       -xy=10<BR>\n" );
document.write( "but i dont know where to go from here </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466869 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+i)(3-iy)= 1+13i\r<BR>\n" );
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document.write( "(3x+y)+(3-xy)i=1+13i\r<BR>\n" );
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document.write( "(1) 3x+y=1, <BR>\n" );
document.write( "(2) 3-xy=13\r<BR>\n" );
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document.write( "(2) 3-xy=13,  xy=-10,  y=-10/x\r<BR>\n" );
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document.write( "(1) 3x+y=1, 3x+(-10/x)=1, 3x^2-x-10=0, x=2, x=-5/3\r<BR>\n" );
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document.write( "then \r<BR>\n" );
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document.write( "(x,y)=(2,-5)\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "(x,y)=(-5/3, 6)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );