document.write( "Question 766331: x^2+4x+c=0
\n" ); document.write( "what value of c does the equation have one real root and what range of value does it have two roots, fo what range of values does the equation have two complex.
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Algebra.Com's Answer #466850 by josgarithmetic(39617)\"\" \"About 
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The general solution, \"x=%28-4%2B-sqrt%284%2A4-4%2A1%2Ac%29%29%2F%282%2A1%29\"
\n" ); document.write( "contains an expression, \"4%5E2-4c\".\r
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\n" ); document.write( "\n" ); document.write( "That is the DISCRIMINANT. It is written in the square root function. \r
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\n" ); document.write( "\n" ); document.write( "Discriminant = 0, then equation has one real root.
\n" ); document.write( "Discriminant greater than zero, then equation has two real roots.
\n" ); document.write( "Discriminant less than zero, then the equation has two complex roots with imaginaries.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2B-sqrt%284-c%29\" when simplified.\r
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\n" ); document.write( "\n" ); document.write( "c=4 makes x be exactly one solution because \"sqrt%284-4%29=0\".
\n" ); document.write( "c<4 makes x be either of two real solutions because \"sqrt%284-c%29\" will itself be a real value.
\n" ); document.write( "c>4 makes \"sqrt%284-c%29\" be imaginary, and there be two complex roots solutions for x with imaginary components.
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