document.write( "Question 65919: solve for x: 4=ln√(x-2) +2\r
\n" ); document.write( "\n" ); document.write( "i can get 2=ln√(x-2) but im not sure what to do after that. Please help thank you in advance. :) <3
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Algebra.Com's Answer #46682 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"4+=+ln%28sqrt%28x-2%29%29%2B2\" Subtract 2 from both sides.
\n" ); document.write( "\"2+=+ln%28sqrt%28x-2%29%29\" Rewrite the right side in exponential form.
\n" ); document.write( "\"2+=+ln%28x-2%29%5E%281%2F2%29\" Apply the power rule for logarithms.
\n" ); document.write( "\"2+=+%281%2F2%29ln%28x-2%29\" Multiply both sides by 2.
\n" ); document.write( "\"ln%28x-2%29+=+4\" Rewrite this in exponential form.
\n" ); document.write( "\"x-2+=+e%5E4\" Add 2 to both sides.
\n" ); document.write( "\"x+=+e%5E4%2B2\" Evaluate.
\n" ); document.write( "\"x+=+54.5982%2B2\"
\n" ); document.write( "\"x+=+56.5982\" Approximately.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"4+=+ln%28sqrt%2856.5982+-+2%29%29%2B2\"
\n" ); document.write( "\"4+=+ln%28sqrt%2854.5982%29%29%2B2\" Use your calculator to evaluate.
\n" ); document.write( "\"4+=+2.0000%2B2\"
\n" ); document.write( "\"4+=+4\"\r
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